Find the area of a rectangle if its perimeter is 24 and one side is twice the size of the other.

1. Vertices of the rectangle – A, B, C, D. S – the area of the parallelogram. AD is 2 times more than AB. Perimeter (P) = 24 units.

2. АD = 2АВ (according to the problem statement).

3. P = 2 (AB + AD) = 24 units.

AB + AD = 12 units. We substitute here AD = 2AB:

AB + 2AB = 12 units of measurement.

AB = 4 units.

АD = 4 х 2 = 8 units of measurement.

4. S = AD x AB = 8 x 4 = 32 units of measurement².

Answer: S is equal to 32 units².



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