Find the area of a rectangle if its perimeter is 244 cm and its width is 58 cm.

Let’s find the length of the given rectangle.

Let us denote it by x.

According to the condition of the problem, the width of this rectangle is 58 cm, and its perimeter is 244 cm.

Since the perimeter of any rectangle is equal to the sum of the length and width of this rectangle multiplied by 2, we can write the following equation:

2 * (x + 58) = 244.

We solve the resulting equation:

x + 58 = 244/2;

x + 58 = 122;

x = 122 – 58;

x = 64 cm.

Find the area S of a given rectangle as the product of the length and width of a given rectangle:

S = 64 * 58 = 3712 cm².

Answer: the area of ​​this rectangle is 3712 cm².