Find the area of a rectangle if its perimeter is 244 cm and its width is 58 cm.

Find the sum of the length and width of this rectangle.

According to the condition of the problem, the perimeter of this rectangle is 244 cm.

Since the perimeter of any rectangle is equal to the sum of the length and width of this rectangle multiplied by 2, the sum of the length and width of this rectangle is:

244/2 = 122 cm.

According to the condition of the problem, the width of this rectangle is 58 cm, therefore, the length of this rectangle is:

122 – 58 = 64 cm.

Knowing the length and width of this rectangle, we find its area:

64 * 58 = 3712 cm².

Answer: the area of ​​this rectangle is 3712 cm².