Find the area of a rectangle, knowing that its perimeter is 1 m, and its width is 10 cm shorter than its length.

Given:
The perimeter P of the rectangle is 1 m.
The width b of the rectangle is 10 cm shorter than the length a.

Let’s convert meters to centimeters:
1 m = 100 cm.
Let the width of the rectangle b be x cm.
Then the length a will be (x + 10) cm.
Let’s make the equation:
x + x + x + 10 + x + 10 = 100;
4x = 100 – 10 – 10;
4x = 80;
x = 80: 4;
x = 20.
The width of this figure is 20 cm.
Let’s find its length:
20 + 10 = 30 cm.
We calculate the area of the rectangle using the formula S = a * b:
S = a * b = 30 * 20 = 600 cm2.
Answer: the area is 600 cm2.