Find the area of a rectangle that is 4 2/5 dm wide and 1 1.2 times wider.

Let’s express all values as improper fractions:

4 2/5 = 22/5;

1 1/2 = 3/2.

Since the length of the rectangle is 3/2 times the width, it is equal to:

22/5 * 3/2 = 66/10 dm.

Then its area is equal to:

22/5 * 66/10 = 1320/50 = 26.4 dm ^ 2.

Answer: the required area is 26.4 dm ^ 2.



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