Find the area of a rectangular trapezoid, the bases of which are 4 and 6 cm, and one of the angles is 135 degrees.
A rectangular trapezoid is called, in which one of the lateral sides is height, so its two corners are straight.
The area of the trapezoid is calculated as the product of the half-sum of its bases by the height:
S = (BC + AD) / 2 h.
Suppose AB is the large side, BH is the height, and the angle B is 135 °.
Consider the triangle ABH. The segment AH is equal to the difference in the length of the bases:
AH = AD – BC;
AH = 6 – 4 = 2 cm.
Since the sum of the degree measures of the angles adjacent to one side is 180 °, the angle A is equal to:
∠А = 180 ° – 135 ° = 45 °.
We can find the BH height by applying the tangent of the angle a:
tg A = BH / AH;
tg 45 ° = 1;
BH = AH · tg A;
BH = 2 1 = 2 cm.
S = (4 + 6) / 2 2 = 10 cm2.
Answer: the area of the trapezoid is 10 cm2.