Find the area of a rhombus if one of its corners is 60 and the perimeter is 8√3.

Since ABCD is a rhombus, the lengths of all its sides are equal.

Then AB = BC = CD = AD = Ravsd / 4 = 8 * √3 / 4 = 2 * √3 cm.

Let’s apply the formula for the area of a rhombus through the length of the sides and the sine of the angle between them.

Savsd = AD * AB * SinBAD = 2 * √3 * 2 * √3 * √3 / 2 = 6 * √3 cm2.

Answer: The area of the rhombus is 6 * √3 cm2.



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