Find the area of a right-angled triangle with a hypotenuse of 29 cm and a leg of 21 cm.

Let’s denote the triangle ABC
1) Because. ABC – rectangular, then S = ½ * AC * CB
By the Pythagorean theorem AB2 = AC2 + CB2
And since AB = 29cm, AC = 21cm, then CB2 = AB2-AC2
CB2 = 29 * 29-21 * 21
CB2 = 400
CB = 20cm
2) S = ½ * 21 * 20
S = 210cm2
answer: 210cm2



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