Find the area of a trapezoid in which the middle line is 6, one base is 10, and the height is equal to the smaller base.

Through the length of the midline of the trapezoid and one of the bases, we determine the length of the second base.

KM = (BC + AD) / 2.

2 * KM = BC + AD.

BC = 2 * KM – AD = 2 * 6 – 10 = 2 cm.

By condition, the length of the height is equal to the length of the smaller base, then BH = BC = 2 cm.

Then the area of the trapezoid is:

Savsd = (АD + ВС) * ВН / 2 = (10 + 2) * 2/2 = 12 cm2.

Answer: The area of the trapezoid is 12 cm2.



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