Find the area of a trapezoid whose vertices have coordinates (1; 1), (10; 1), (8; 7), (5; 7)
| September 6, 2021 | education
The length of the larger base of the trapezoid is: AD = (10 – 1) = 9 cm.
The length of the smaller base of the trapezoid is: BC = (8 – 5) = 3 cm.
The length of the height BH of the trapezoid is: BH = (7 – 1) = 6 cm.
Determine the area of the trapezoid.
Savsd = (AD + AB) * BH / 2 = (9 + 3) * 6/2 = 36 cm2.
Answer: The area of the trapezoid is 36 cm2.
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