Find the area of a trapezoid whose vertices have coordinates (2; 1), (10; 0), (10; 6), (2; 8).

Mark the points on the coordinate plane and connect them. ABCD – trapezoid with bases AD and CD.

Length АD = 6 – 0 = 6 cm, length of СSD = 8 – 1 = 7 cm.

Let’s build the height of the HВ.

Length BH = 10 – 2 = 8 cm.

Determine the area of the trapezoid.

Savsd = (AD + ВС) * ВН / 2 = (6 + 7) * 8/2 = 13 * 4 = 52 cm2.

Answer: The area of the trapezoid is 52 cm2.



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