Find the area of a triangle ABC if BC = 3 cm, AB = 18√2 cm, angle B = 45.

From the school curriculum in geometry, we know for sure, one of the options in order to calculate the area of such a figure is to use the following formula:

S = a * b * sin a: 2, sin a is the sine of the angle that will be between sides a and b.

We find out what size the area of our geometric figure will correspond to, when from the condition we know that the lengths of the sides are 3 and 18√2 centimeters, and the angle is 45 °:

1/2 * 3 * 18√2 * √2 / 2 = 1.5 * 18 = 27.

Answer: The area is 27 cm2.