Find the area of a triangle if a = 13.5 b = 12.2 ∠C = 60 °

Let us drop the height h from the vertex B to the side b.

The BKC triangle is rectangular.

h / a = sin c;

h = a * sin c.

Area of a triangle:

S = hb / 2 = (ab * sin c) / 2 = (13.5 * 12.2 * (√3 / 2)) / 2 = (13.5 * 12.2 * √3) / 4 = 71 , 31.

Answer: the area of the triangle is S = 71.31.



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