Find the area of a triangle if the angle is B = 60 degrees bc = 14 ab = 3.
August 27, 2021 | education|
Let in the triangle ABC AB = 3, BC = 14, <B = 60,
Find the area S (ABC) = 1/2 * AB * BC * sin B = 1/2 * 3 * 14 * sin 60 = 21 * √3 / 2 = 10.5 * √3.
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