Find the area of a triangle whose vertices have coordinates (1; 1) (1; 4) (4; 3).

Let A (1; 1), (B1; 4), C (4; 3).

By the coordinates of the vertices of the triangle ABC, we determine the lengths of its sides.

AB = √ (X1 – X2) ^ 2 + (Y1- Y2) ^ 2 = √ (1 – 1) ^ 2 + (4 – 1) ^ 2 = √9 = 3 cm.

Determine the height of the CH.

CH = 4 – 1 = 3 cm.

Determine the area of the triangle ABC.

Savs = AB * CH / 2 = 3 * 3/2 = 4.5 cm2.

Answer: The area of the triangle ABC is 4.5 cm2.



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