Find the area of a triangle whose vertices have coordinates (9; 7) (9; 10) (3; 2)

Given: ▲ ABC. A (9; 7), B (9; 10), C (3; 2).

Find S ▲ ABC.

The area of a triangle according to the known coordinates of its vertices A (x1, y1), B (x2, y2), C (x3, y3) is calculated by the formula:

S = 1/2 [(x1 – x3) (y2 – y3) – (x2 – x3) (y1 – y3)].

S = 1/2 [(1 – 8) (7 – 9) – (4 – 8) (7 – 9)] = 1/2 (14 – 8) = 3.

Answer: 3 square units.



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