Find the area of an even triangle whose base is 24cm and the side is 13cm.

The area of ​​a triangle is equal to the half-product of the side and the height dropped on that side. Let’s draw the height to the base of the isosceles triangle. In an isosceles triangle, the height is also the bisector and the median (according to its properties). The height divided the isosceles triangle into two identical right-angled triangles, in which it is the leg. Let’s find the unknown leg according to the Pythagorean theorem:

a² + b² = c²;

a² + 12² = 13²;

a² + 144 = 169;

a² = 169 – 144;

a² = 25;

a = 5 cm – the height of the triangle.

Find the area:

S = 1/2 * a * ah;

S = 1/2 * 24 * 5;

S = 60 cm².

Answer: 60 cm²