Find the area of an isosceles right-angled triangle with a hypotenuse of 14 cm.

Since the triangle is equilateral and rectangular, the square of the hypotenuse is equal to two squares of the leg.

Let the leg be equal to X cm, then:

2 * X ^ 2 = 14 ^ 2.

X ^ 2 = 196/2 = 98.

Then the area of the triangle is: S = X ^ 2/2 = 98/2 = 49 cm2.

Answer: The area of the triangle is 49 cm2.



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