Find the area of an isosceles trapezoid ABCD with bases BC and AD if AB = 13m BC = 16m height CH = 12m.

S = 1/2 (BC + AD) * CH;

The CDH triangle is rectangular. By the Pythagorean theorem:

HD² = CD² – CH²;

Since the trapezoid ABCD is isosceles, then CD = AB = 13 m;

HD² = 13² – 12² = 169 – 144 = 25 (m²)

HD = 5 m;

AD = BC + 2 HD = 16 + 2 * 5 = 26 (m);

S = 1/2 (16 + 26) * 12 = 1/2 * 42 * 12 = 252 (m²).



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