Find the area of an isosceles trapezoid if its smaller base is 7cm, the side is 10cm, and the height is 8cm.

Given a trapezoid ABCD:

BC = 7 cm;
AB = CD = 10 cm;
BH = 8 cm;
S =?
AH = √ (AB² – BH²) = √ (10² – 8²) = √ (100 – 64) = √36 = 6 (cm);
AD = BC + 2 * AH = 7 + 2 * 6 = 19 (cm);
S = 1/2 * BH * (AD + BC) = 1/2 * 8 * (19 + 7) = 4 * 26 = 104 (cm²).



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