Find the area of an isosceles triangle with a side of 16cm and an angle of 15 degrees at the base.

Let’s designate a triangle ABC, AC – base, AB, BC – lateral sides.
We find the area of a triangle as half of the product of two sides and the sine of the angle between these sides.
By the condition of the problem, we know the lateral side of an isosceles triangle 16 cm, respectively, and the second lateral side – 16 cm.Let’s find the angle between them or the angle at the apex of the isosceles triangle:
∠ B = 180 ° – 2 * 15 ° = 180 ° – 30 ° = 150 °.
Find the area:
S = 1/2 * AB * BC * sin B = 1/2 * 16 * 16 * 1/2 = 64 (cm²).
Answer: the area of the triangle is 64 cm².