Find the area of an isosceles triangle with sides 10cm, 10cm and 12cm.

In the triangle ABC – AB = BC = 10 cm; AC = 12 cm; ВK – height;

S = 1/2 AC * BK;

BK² = AB² = AK²; AK = 1/2 AC = 6 cm, as the height in an isosceles triangle

is the median;

BK² = 100 – 36 = 64 (cm²);

BK = 8 cm;

S = 1/2 * 12 * 8 = 48 (cm²);



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