Find the area of the rectangle ABCD if: a) A (2; 2), B (2; 7), C (10; 7), D (10,2) b)

| July 24, 2021 | education

Find the area of the rectangle ABCD if: a) A (2; 2), B (2; 7), C (10; 7), D (10,2) b) A (-9; -3), B (- 2, -3), C (-2; -8), D (-9; -8) The length of a unit segment is 1cm.

To find the area of a rectangle, we first calculate what its sides are equal to. Points A and B, as well as points C and D, have the same x coordinate, which means sides AB and CD are parallel to the ordinate axis. The sides BC and AD are similarly parallel to the abscissa axis. Therefore, to find the length of the side, you just need to find the difference in the corresponding coordinates modulo.

a) AB = 7 – 2 = 5 cm

AD = 10 – 2 = 8 cm

S = AB * AD

S = 5 * 8 = 40 cm2.

Answer: the area is 40 cm2.

b) AB = | -9 – (-2) | = 7 cm

AD = | -8 – (-3) | = 5 cm

S = AB * AD

S = 5 * 7 = 35 cm2.

Answer: the area is 35 cm2.



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