Find the area of the trapezoid if the bases are 30 cm and 40 cm, the obtuse angle is 150 degrees, the lateral side is 20 cm.

1. The tops of the trapezoid – A, B, C, D. ∠B = 150 °. BC = 30 cm AD = 40 cm AB = 20 cm BE – height.

S is the area of the trapezoid.

2. ∠ABE = ∠B – ∠CBE = 150 ° – 90 ° = 60 °.

3. We calculate the length of the height BE through the cosine ∠ABE, equal to the ratio of the height of BE, which is a leg in a right-angled triangle ABE, to the hypotenuse AB of the indicated triangle:

BE / AB = cosine ∠ABE = cosine 60 ° = 1/2.

BE = AB x 1/2 = 20 x 1/2 = 10 cm.

S = (AD + BC) / 2 x BE = (40 + 30) / 2 x 10 = 350 cm².

Answer: S is equal to 350 cm².



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