Find the average kinetic energy of atoms of a monatomic gas at a pressure of 20 kPa.

Find the average kinetic energy of atoms of a monatomic gas at a pressure of 20 kPa. The concentration of atoms of this gas is 3 • 10_25 m_-3

Problem data: P (pressure of a given monatomic gas) = 20 kPa (20 * 10 ^ 3 Pa); n (concentration of a given gas) = 3 * 10 ^ 25 m-3.

To find the average kinetic energy of atoms of a given gas, we use the formula: P = 2/3 * n * Ek, from which we express Ek = 3P / 2n.

Let’s calculate: Ek = 3 * 20 * 10 ^ 3 / (2 * 3 * 10 ^ 25) = 1 * 10 ^ -21 J.

Answer: The required average kinetic energy of atoms of a given gas is 1 * 10 ^ -21 J.