Find the ceiling height of the school assembly hall if its width is 21.2 m, length is 27.5 m, and the volume is 3672.9 m3.

1) From the conditions of this problem, we know that the width of the school assembly hall is 21.2 meters, the width is 21.2 meters, the length is 27.5 meters, and the volume is 3672.9 m3. Find from the formula V = a * b * h the height (h). For this:
h = V / a * b = 3672.9 / 27.5 * 21.2 = 3672.9 / 583 = 6.3 (m) – the height of the school assembly hall.
Answer to the problem: The height of the school assembly hall is 6 meters 30 centimeters.