Find the change in the internal energy of 0.50m ^ 3 ammonia gas nh3 with an increase in pressure of 4.0 kPa.

These tasks: V (volume of taken ammonia gas) = 0.5 m3; ΔP (pressure increase) = 4 kPa (4 * 10 ^ 3 Pa); isochoric process.

Reference values: i (the number of degrees of freedom for molecules of polyatomic gases (NH3 is a tetraatomic gas)) = 6.

The change in the internal energy of the taken ammonia gas is determined by the formula: ΔU = 0.5 * i * V * ΔР.

Let’s perform the calculation: ΔU = 0.5 * 6 * 0.5 * 4 * 10 ^ 3 = 6 * 10 ^ 3 J (6 kJ).

Answer: The internal energy of the taken ammonia gas will increase by 6 kJ.