Find the chord length of a circle with radius 13 if the distance from the center of the circle to the chord is 5.

Let’s construct and introduce the notation. Consider triangles AOH and BOH (they are rectangular), – OH is common, AO and OB are equal as the radii of a circle, therefore, these triangles are equal, whence AH = HB = AB / 2 By the Pythagorean theorem, we find the length of the segment AH: AH = √AO ^ 2-OH ^ 2 = √13 ^ 2-5 ^ 2 = √ (13-5) (13 + 5) = √8 * 18 = √9 * 16 = 3 * 4 = 12 => AB = 2AH = 2 * 12 = 24
Answer: 24cm