Find the coordinates of the intersection of the graphs of the functions: y = 47x-37 and y = -21x-36

These functions are linear, which means that their graphs will be straight lines with one intersection point. Therefore, x1 = x2 and y1 = y2. Using the last equality, we have:
y1 = 47x – 37, y2 = -21x – 36.
47x – 37 = -21x – 36.
47x + 21x = -36 + 37.
68x = 1.
x = 1/68.
Substitute the found value of the abscissa of the point of intersection of the graphs into the first equation, we get:
1/68 = 47x – 37.
47x = 1/68 + 37.
x = (1/68 + 37) / 47.
x = -36 21/68.
Answer: (-36 21/68; 1/68).