Find the coordinates of the midpoints of the sides of the triangle with vertices A (0; 0), B (0; 4) and C (-6; 0)
| August 16, 2021 | education
Midpoint of segment AB:
xser = (0 + 0) / 2 = 0;
yser = (0 + 4) / 2 = 2.
Answer: (0; 2).
Midpoint of segment AC:
xser = (0 – 6) / 2 = – 3;
yser = (0 + 0) / 2 = 0.
Answer: (- 3; 0).
Midpoint of segment BC:
xser = (0 – 6) / 2 = – 3;
yser = (4 + 0) / 2 = 2.
Answer: (- 3; 2).
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