Find the coordinates of the points of intersection of the graph of the linear equation -3x + 2y-6 = 0 with the axes to the ordinates.

In order to find the coordinates of the points of intersection of the graph of the linear equation -3x + 2y – 6 = 0 with the coordinate axes, you and I will have to solve two linear equations.

In order to find the point of intersection with the OX axis, we must substitute y = 0 into the given equation of the straight line and solve the resulting equation of the system.

-3x + 2 * 0 – 6 = 0;

-3x – 6 = 0;

We solve the resulting equation:

-3x = 6;

x = 6: (-3);

x = -2.

(-twenty).

We are looking for the point of intersection with the OY axis – x = 0.

-3 * 0 + 2 * y – 6 = 0;

2y – 6 = 0;

2y = 6;

y = 3.

(0; 3).