Find the density of helium at 0 ° C and a pressure of 20 kPa.

Data: Т (absolute temperature of helium) = 0 ºС = 273 К; P (helium pressure) = 20 kPa (20 * 10 ^ 3 Pa).

Constants: R (universal gas constant) = 8.31 J / (mol * K); M (molar mass of helium, monatomic gas) = 4 g / mol (4 * 10 ^ -3 kg / mol).

The density of helium with the given parameters can be determined using the Mendeleev-Clapeyron law: P * V = (m / M) * R * T and ρ = P * M / (R * T).

Calculation: ρ = 20 * 10 ^ 3 * 4 * 10 ^ -3 / (8.31 * 273) = 0.035 kg / m3.

Answer: Helium will have a density of 0.035 kg / m3.



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