Find the density of hydrogen at a pressure of 41 kPa and a temperature of 243 K.

Initial data: P (hydrogen pressure) = 41 kPa = 41 * 10 ^ 3 Pa; T (absolute temperature of hydrogen) = 243 K.

Reference values: M (molar mass of hydrogen) = 2 g / mol = 0.002 kg / mol; R (universal gas constant) = 8.31 J / (mol * K).

The density of hydrogen under given conditions is determined from the formula:

P * V = (m / M) * R * T, whence ρ = m / V = P * M / (R * T).

Let’s perform the calculation: ρ = 41 * 10 ^ 3 * 0.002 / (8.31 * 243) ≈ 0.041 kg / m3.

Answer: The density of hydrogen under the given conditions is 0.041 kg / m3.