Find the density of oxygen at a temperature of 27 degrees and a pressure of 160 kPa.

We solve using the Mendeleev-Clapeyron equation PV = m / M * R * T, transfer the volume V, to the right side, we get P = m * R * T / V * M, divide the mass by volume = density:
m / V = po, substitute and express the density po.
p = (po) * R * T / M, po = p * M / R * T. (p-pressure = 160000 Pa, M – molar mass of oxygen = 0.032 kg / mol,
R-universal gas constant = 8.31 J / mol * K,
T – absolute temperature = 273 + 27 = 300 K).
ro = 160000 * 0.032 / 8.31 * 300 = 2.054 kg / cu. m.
ro = 2.33 kg / cu. m.