Find the depth at which kerosene exerts a pressure of 2400 Pa. (Kerosene density 800 kg / m3)

P = 2400 Pa.

ρк = 800 kg / m3.

g = 10 m / s2.

h -?

The pressure of a fluid P with a density ρ at a depth h is called hydrostatic and is determined by the formula: P = ρ * g * h, where g is the acceleration of gravity. The fluid pressure at this depth is the same in all directions.

Since in our case the liquid is kerosene, the density of which is ρк = 800 kg / m3, the depth h will be determined by the formula: h = Р / ρк * g.

h = 2400 Pa / 800 kg / m3 * 10 m / s2 = 0.3 m.

Answer: this pressure P = 2400 Pa in kerosene will be at a depth of h = 0.3 m.

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