Find the derivative of the function y = -6x + 1

y = -6x + 1
y ‘= (-6x + 1)’
y ‘= (-6x)’ + (1) ‘
The derivative of a constant number is always 0, so (1) ‘= 0
The derivative of a monomial with a variable in the first degree is equal to the coefficient of the variable in the monomial (-6x) ‘= -6
y ‘= -6 + 0
y ‘= -6
Answer: y ‘= -6



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