Find the diagonal of the axial section of the cylinder if the radius of the cylinder is 1.5m and the height is 4m.

The height of the cylinder is h = 4 m. The base radius is R = 1.5 m. It is necessary to find the length of the ВD diagonal.

Consider the СВD triangle: the angle C is 90 ° (since the section of the AВСD is perpendicular to the base of the cylinder), BC is the height of the cylinder, BC = 4 m.

СD is the diameter of the base, СD = 2R = 2 * 1.5 = 3 m.

By the Pythagorean theorem: ВD = √ (BC² + SD²) = √ (4² + 3²) = √ (16 + 9) = √25 = 5 m.

Answer: the diagonal of the axial section of the cylinder is 5 m.



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