Find the diagonals of a rhombus if one of them is 2.3 times larger than the other, and the area of the rhombus is 46 cm2.

Let one of the diagonals of the rhombus be equal to X cm, then, by condition, the length of the other diagonal is equal to 2.3 * X.

Since the area of a rhombus is half the product of its diagonals, then:

46 = X * 2.3 * X / 2.

2.3 * X2 = 92.

X2 = 92 / 2.3 = 40.

X = √20 = 2 * √10 cm.

Then the second diagonal will be 2.3 * 2 * √10 = 4.6 * √10 cm.

Answer: The diagonals of the rhombus are 2 * √10 cm and 4.6 * √10 cm.