Find the efficiency of the engine if 500 g of fuel with a calorific value of 48 MJ / kg were spent to perform work in 2.4 MJ

These tasks: Ap (work done by the engine used) = 2.4 MJ (2.4 * 10 ^ 6 J); m (mass of fuel consumed) = 500 g (in SI m = 0.5 kg).
Reference values: q (specific heat of combustion of fuel consumed) = 48 MJ / kg (48 * 10 ^ 6 J / kg).
The efficiency of the motor used is determined by the formula: η = Ap / Q = Ap / (q * m).
Calculation: η = 2.4 * 10 ^ 6 / ((48 * 10 ^ 6) * 0.5) = 0.1 or 10%.
Answer: The motor used has an efficiency of 10%.