Find the electric field strength at a distance of 5 cm from the 10 nC charge.

q = 10 nC = 10 * 10 ^ -9 C.

k = 9 * 10 ^ 9 N * m2 * Cl-2.

r = 5 cm = 0.05 m.

E -?

The electric field strength E is a power characteristic that characterizes a given point of the electric field. The strength of the electric field E is determined by the ratio of the force of the electrostatic force F, which acts on the charge at a given point of the field, to the value of the charge itself q: E = F / q.

So the electrostatic force of interaction of charges F is determined by Coulomb’s law, then the formula for determining the strength of a given point of the field will have the form: E = F / q1 = k * q1 * q / r ^ 2 * q1 = k * q / r1 ^ 2.

E = 9 * 10 ^ 9 N * m2 * Cl-2 * 10 * 10 ^ -9 Cl / (0.05 m) ^ 2 = 36000 N / Cl.

Answer: at a given point of the electrostatic field, the intensity is E = 36,000 N / C.