Find the EMF and the internal resistance of the galvanic cell, if with an external circuit resistance of 2 Ohm

Find the EMF and the internal resistance of the galvanic cell, if with an external circuit resistance of 2 Ohm the current is 0.6A, and with a resistance of 1 Ohm the current is 1A.

To solve the problem, an equation can be drawn up, since it is known that when the load resistance R1 is equal to 2 Ohm, the current I1 is 0.6 A, and when the load resistance R2 is equal to 1 Ohm, the current I2 = 1 A. Let’s denote the EMF – U, and the internal resistance of the galvanic cell r:
R1 * I1 + r * I1 = R ^ 2 * I ^ 2 + r * I ^ 2 = U;
2 * 0.6 + 0.6r = 1 * 1 + r;
1.2 – 1 = 0.4r;
0.4r = 0.2;
r = 0.5 Ohm;
U = 1 + 0.5 = 1.5 V.
Answer: The EMF of the galvanic cell is 1.5 V, the internal resistance is 0.5 Ohm.