Find the EMF of induction in a coil containing 300 turns, if the magnetic flux has increased
| July 10, 2021 | education
Find the EMF of induction in a coil containing 300 turns, if the magnetic flux has increased from 5 m Wb to 15 m Wb in 0.2 m.
n = 300.
t = 0.2 m = 12 s.
F1 = 5 mVb = 0.005 Vb.
F2 = 15 mVb = 0.015 Vb.
EMF -?
According to Faraday’s law of electromagnetic induction, the EMF of induction, which occurs in a frame of one turn, is determined by the formula: EMF = – ΔF / t, where ΔF is the change in the magnetic flux, t is the time during which the magnetic flux changes.
Since the coil consists of n turns, the EMF = – n * ΔF / t.
The “-” sign shows the direction of the induction current in the conductor.
ΔФ = Ф2 – Ф1.
EMF = n * (Ф2 – Ф1) / t.
EMF = 300 * (0.015 Wb – 0.005 Wb) / 12 s = 0.25 V.
Answer: EMF = 0.25 V appears in the coil.
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