Find the energy of the magnetic field of a solenoid in which, at a current of 2 kA, a magnetic flux of 0.3 Vb occurs.
| May 1, 2021 | education
To find out the energy of the magnetic field of the indicated solenoid, consider the formula: Wm = 0.5 * I * F.
Data: I – current in the indicated solenoid (I = 2 kA = 2 * 10 ^ 3 A); Ф – created magnetic flux (Ф = 0.3 Wb).
Let’s make a calculation: Wm = 0.5 * I * F = 0.5 * 2 * 10 ^ 3 * 0.3 = 300 J.
Answer: The energy of the magnetic field of the indicated solenoid is 300 J.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
