Find the equation of a circle centered at point A (3; 1) and passing through point B (6; 5)
| June 3, 2021 | education
The radius of the circle is equal to AB:
AB = ((6-3) ^ 2 + (5 – 1) 2) ^ 0.5 = 5.
Circle equation:
(x – 3) ^ 2 + (y – 1) ^ 2 = 25.
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