# Find the first term and denominator of the geometric progression b4 = 8 b8 = 128.

We use the formula for the nth term of the geometric progression bn = b1 * qn – 1,

where b1 is the first term of the geometric progression, q is the denominator of the geometric progression.

According to the problem statement, in this geometric progression b4 = 8, b8 = 128.

Applying the formula for the nth term of the geometric progression for n = 4 and n = 8, we obtain the following relations:

b1 * q4 – 1 = 8;

b1 * q8 – 1 = 128.

Dividing the second ratio by the first, we get:

q7 / q3 = 128/8;

q4 = 16;

q4 = 24;

q1 = -2;

q2 = 2.

Substituting the found value of q into the ratio b1 * q3 = 8, we find b1.

For q = -2:

b1 = 8 / q3 = 8 / (-2) 3 = 8 / (-8) = -1.

For q = 2:

b1 = 8 / q3 = 8/23 = 8/8 = 1.

Answer: the first term and denominator of this geometric progression can have two pairs of values: b1 = 1, q = 2 and b1 = -1, q = -2.