Find the first term of a geometric progression (Xn) if x5 = -64; q = -2.
August 10, 2021 | education
| Given: (Xn) – geometric progression;
x5 = -64, q = -2;
Find: x1 -?
Formula of the nth term of a geometric progression:
xn = x1 * q ^ (n-1), where:
x1 is the first term of the progression, q is the denominator of the progression.
This means that the fifthsq term of a given progression can be written in the following form:
x5 = x1 * q ^ (5-1) = x1 * q ^ 4.
Substituting all the quantities known by the condition into the resulting expression, we get:
x1 * (-2) ^ 4 = -64;
x1 * 16 = -64;
x1 = -64: 16;
x1 = -4.
Answer: x1 = -4.
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