Find the force of attraction of bodies with masses of 20 tons and 12 tons at a distance of 25 cm from each other.

m1 = 20 t = 20,000 kg.

m2 = 12 t = 12000 kg.

G = 6.67 * 10 ^ -11 H * m2 / kg2.

r = 25 cm = 0.25 m.

F -?

According to the law of universal gravitation, the force of mutual attraction F, which arises between the bodies, is directly proportional to the masses of the interacting bodies m1 and m2, and inversely proportional to the square of the distance between them R2: F = G * m1 * m2 / R ^ 2, where G is the coefficient of proportionality , which is called the gravitational constant.

F = 6.67 * 10 ^ -11 H * m2 / kg2 * 20,000 kg * 12,000 kg / (0.25 m) ^ 2 = 0.26 N.

Answer: a force of mutual attraction F = 0.26 N. acts between the bodies.



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