Find the force of gravity acting on 20 liters of sunflower oil. The length of the spring changed by 2.8 cm

Find the force of gravity acting on 20 liters of sunflower oil. The length of the spring changed by 2.8 cm under the action of a force of 4 N. What is the coefficient of elasticity? how does the weight of a body differ from the force of gravity acting on it?

1) V = 20 l = 0.02 m3.

ρ = 930 kg / m3.

g = 10 m / s2.

Fт -?

Fт = m * g.

m = V * ρ.

Fт = V * ρ * g.

Ft = 0.02 m3 * 930 kg / m3 * 10 m / s2 = 186 N.

Answer: gravity Ft = 186 N. acts on sunflower oil.

2) F = 4 N.

x = 2.8 cm = 0.028 m.

k -?

k = F / x.

k = 4 N / 0.028 m = 142.9 N / m.

Answer: k = 142.9 N / m.

m = V * ρ.

3) The force of gravity acts on the body, and the weight is the force with which the body presses on the support or stretches the suspension. Gravity is independent of body movement, and body weight depends on body movement.



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