Find the force of interaction between bodies with charges of 15 C and 20, if they are located at a distance of 3 m from each other.

Given:
q1 = 15Cl
q2 = 20cl
R = 3m
Find: F =? H
Decision:
F = (k * q1 * q2) / R ^ 2
F = (9 * 10 ^ 9 * 15 * 20) / 9 = 300 * 10 ^ 9 = 300 GN (G- prefix giga equal to 10 ^ 9)
Answer: 300 GN.



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