Find the force of interaction between positive and negative point charges 1μC located at a distance of 10cm.

Problem data: q1 = q2 = q (modulus of each of the charges) = 1 μC (1 * 10 ^ -6 C); r (the distance at which the charges are located) = 10 cm (in SI r = 0.1 m).

Reference values: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

The force of interaction between the taken point charges is determined by the formula: F = k * q1 * q2 / r ^ 2 = k * q ^ 2 / r ^ 2.

Let’s make a calculation: F = 9 * 10 ^ 9 * (1 * 10 ^ -6) ^ 2 / 0.12 = 0.9 N.

Answer: The sought force of interaction of the taken point charges is 0.9 N.